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Integers Ex-1.2

NCERT solutions for Class 7 Integers Maths 

NCERT Solutions for Class 7 Maths Exercise 1.2

NCERT Solutions for Class 7 Maths Integers

Class –VII Mathematics (Ex. 1.2)
Question 1.Write down a pair of integers whose:

(a) sum is 7– 7

(b) difference is 10– 10

(c) sum is 0

Answer:

(a) One such pair whose sum is 7– 7: 5+(2)=7– 5 + \left( { – 2} \right) = – 7

(b) One such pair whose difference is 10– 10: 28=10– 2 – 8 = – 10

(c) One such pair whose sum is 0: 5+5=0– 5 + 5 = 0


NCERT Solutions for Class 7 Maths Exercise 1.2

Question 2.(a) Write a pair of negative integers whose difference gives 8.

(b) Write a negative integer and a positive integer whose is 5.– 5.

(c) Write a negative integer and a positive integer whose difference is 3.– 3.

Answer:

(a) 2(10)2+10=8– 2 – \left( { – 10} \right) – 2 + 10 = 8

(b) (7)+2=5\left( { – 7} \right) + 2 = – 5

(c) (2)1=21=3\left( { – 2} \right) – 1 = – 2 – 1 = – 3


NCERT Solutions for Class 7 Maths Exercise 1.2

Question 3.In a quiz, team A scored 40,10,0– 40,10,0 and team B scores 10, 0, 40– 40 in three successive rounds. Which team scored more? Can we say that we can add integers in any order?

Answer:

Team A scored 40,10,0– 40,10,0

Total score of Team A = 40+10+0=30– 40 + 10 + 0 = – 30

Team B scored 10,0,4010,0, – 40

Total score of Team B = 10+0+(40)=10+040=3010 + 0 + \left( { – 40} \right) = 10 + 0 – 40 = – 30

Thus, scores of both teams are same.

Yes, we can add integers in any order due to commutative property.


NCERT Solutions for Class 7 Maths Exercise 1.2

Question 4.Fill in the blanks to make the following statements true:

(i)(5)+(8)=(8)+(.)\left( { – 5} \right) + \left( { – 8} \right) = \left( { – 8} \right) + \left( {…….} \right)

(ii)53+.=53– 53 + ……. = – 53

(iii)17 + ……. = 0

(iv)[13+(12)]+(.)=13+[(12)+(7)]\left[ {13 + \left( { – 12} \right)} \right] + \left( {…….} \right) = 13 + \left[ {\left( { – 12} \right) + \left( { – 7} \right)} \right]

(v)(4)+[15+(3)]=[4+15]+.\left( { – 4} \right) + \left[ {15 + \left( { – 3} \right)} \right] = \left[ { – 4 + 15} \right] + …….

Answer:

(i) (5)+(8)=(8)+(5)\left( { – 5} \right) + \left( { – 8} \right) = \left( { – 8} \right) + \underline {\left( { – 5} \right)} [Commutative property]

(ii) 53+0=53– 53 + \underline 0 = – 53 [Zero additive property]

(iii) 17+(17)=017 + \underline {\left( { – 17} \right)} = 0 (Additive identity]

(iv)[13+(12)]+(7)=13+[(12)+(7)]\left[ {13 + \left( {12} \right)} \right] + \underline {\left( { – 7} \right)} = 13 + \left[ {\left( { – 12} \right) + \left( { – 7} \right)} \right] [Associative property]

(4)+[15+(3)]=[4+15]+(3)\left( { – 4} \right) + \left[ {15 + \left( { – 3} \right)} \right] = \left[ { – 4 + 15} \right] + \underline {\left( { – 3} \right)} [Associative property]


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