Fractions and Decimals Ex-2.6

NCERT solutions for Maths Fractions and Decimals 

NCERT Solutions for Class 7 Maths Fractions and Decimals

Class –VII Mathematics (Ex. 2.6)

Question 1.Find:

(i) 0.2 x 6

(ii) 8 x 4.6

(iii) 2.71 x 5

(iv) 20.1 x 4

(v) 0.05 x 7

(vi) 211.02 x 4

(vii) 2 x 0.86

Answer:

(i) 0.2 x 6 = 1.2

(ii) 8 x 4.6 = 36.8

(iii) 2.71 x 5 = 13.55

(iv) 20.1 x 4 = 80.4

(v) 0.05 x 7 = 0.35

(vi) 211.02 x 4 = 844.08

(vii) 2 x 0.86 = 1.72

NCERT Solutions for Class 7 Maths Exercise 2.6

Question 2.Find the area of rectangle whose length is 5.7 cm and breadth is 3 cm.

Answer:

Given: Length of rectangle = 5.7 cm and Breadth of rectangle = 3 cm

Area of rectangle = Length x Breadth

= 5.7 x 3 = 17.1$c{m^2}$

Thus, the area of rectangle is 17.1 $c{m^2}$.

NCERT Solutions for Class 7 Maths Exercise 2.6

Question 3.Find:

(i) 1.3 x 10

(ii) 36.8 x 10

(iii) 153.7 x 10

(iv) 168.07 x 10

(v) 31.1 x 100

(vi) 156.1 x 100

(vii) 3.62 x 100

(viii) 3.07 x 100

(ix) 0.5 x 10

(x) 0.08 x 10

(xi) 0.9 x 100

(xii) 0.03 x 1000

Answer:

(i) 1.3 x 10 = 13.0

(ii) 36.8 x 10 = 368.0

(iii) 153.7 x 10 = 1537.0

(iv) 168.07 x 10 = 1680.7

(v) 31.1 x 100 = 3110.0

(vi) 156.1 x 100 = 15610.0

(vii) 3.62 x 100 = 362.0

(viii) 43.07 x 100 = 4307.0

(ix) 0.5 x 10 = 5.0

(x) 0.08 x 10 = 0.80

(xi) 0.9 x 100 = 90.0

(xii) 0.03 x 1000 = 30.0

NCERT Solutions for Class 7 Maths Exercise 2.6

Question 4.A two-wheeler covers a distance of 55.3 km in one litre of petrol. How much distance will it cover in 10 litres of petrol?

Answer:

$\because$ In one litre, a two-wheeler covers a distance = 55.3 km

$\therefore$ In 10 litrs, a two- wheeler covers a distance = 55.3 x 10 = 553.0 km

Thus, 553 km distance will be covered by it in 10 litres of petrol.

NCERT Solutions for Class 7 Maths Exercise 2.6

Question 5.Find:

(i) 2.5 x 0.3

(ii) 0.1 x 51.7

(iii) 0.2 x 316.8

(iv) 1.3 x 3.1

(v) 0.5 x 0.05

(vi) 11.2 x 0.15

(vii) 1.07 x 0.02

(viii) 10.05 x 1.05

(ix) 101.01 x 0.01

(x) 100.01 x 1.1

Answer:

(i) 2.5 x 0.3 = 0.75

(ii) 0.1 x 51.7 = 5.17

(iii) 0.2 x 316.8 = 63.36

(iv) 1.3 x 3.1 = 4.03

(v) 0.5 x 0.05 = 0.025

(vi) 11.2 x 0.15 = 1.680

(vii) 1.07 x 0.02 = 0.0214

(viii) 10.05 x 1.05 = 10.5525

(ix) 101.01 x 0.01 = 1.0101

(x) 100.01 x 1.1 = 110.11