Fractions and Decimals Ex-2.4

NCERT solutions for Maths Fractions and Decimals 

NCERT Solutions for Class 7 Maths Fractions and Decimals

Class –VII Mathematics (Ex. 2.4)

Question 1.Find:

(i) $12 \div \frac{3}{4}$

(ii) $14 \div \frac{5}{6}$

(iii) $8 \div \frac{7}{3}$

(iv) $4 \div \frac{8}{3}$

(v) $3 \div 2\frac{1}{3}$

(vi) $5 \div 3\frac{4}{7}$

Answer:

(i) $12 \div \frac{3}{4}$ = $12 \times \frac{4}{3}$ = 16

(ii)$14 \div \frac{5}{6}$ = $14 \times \frac{6}{5} = \frac{{84}}{5} = 16\frac{4}{5}$

(iii) $8 \div \frac{7}{3}$ = $8 \times \frac{3}{7} = \frac{{24}}{7} = 3\frac{3}{7}$

(iv) $4 \div \frac{8}{3}$ = $4 \times \frac{3}{8} = \frac{3}{2} = 1\frac{1}{2}$

(v) $3 \div 2\frac{1}{3}$ = $3 \div \frac{7}{3} = 3 \times \frac{3}{7} = \frac{9}{7} = 1\frac{2}{7}$ (vi) $5 \div 3\frac{4}{7}$ = $5 \div \frac{{25}}{7} = 5 \times \frac{7}{{25}} = \frac{7}{5} = 1\frac{2}{5}$

NCERT Solutions for Class 7 Maths Exercise 2.4

Question 2. Find the reciprocal of each of the following fractions. Classify the reciprocals as proper fraction, improper fractions and whole numbers.

(i) $\frac{3}{7}$

(ii) $\frac{5}{8}$

(iii) $\frac{9}{7}$

(iv) $\frac{6}{5}$

(v) $\frac{{12}}{7}$

(vi) $\frac{1}{8}$

(vii) $\frac{1}{{11}}$

Answer:

(i) Reciprocal of $\frac{3}{7}{\text{ }} = {\text{ }}\frac{7}{3}{\text{ }}\xrightarrow{{}}$ Improper fraction

(ii) Reciprocal of $\frac{5}{8}{\text{ }} = {\text{ }}\frac{8}{5}{\text{ }}\xrightarrow{{}}$ Improper fraction

(iii) Reciprocal of $\frac{9}{7}{\text{ }} = {\text{ }}\frac{7}{9}{\text{ }}\xrightarrow{{}}$ Proper fraction

(iv) Reciprocal of $\frac{6}{5}{\text{ }} = {\text{ }}\frac{5}{6}{\text{ }}\xrightarrow{{}}$ Proper fraction

(v)Reciprocal of $\frac{{12}}{7}{\text{ }} = {\text{ }}\frac{7}{{12}}{\text{ }}\xrightarrow{{}}$ Proper fraction

(vi) Reciprocal of $\frac{1}{8}{\text{ }} = {\text{ 8 }}\xrightarrow{{}}$ Whole number

(vi) Reciprocal of $\frac{1}{{11}}{\text{ }} = {\text{ 11 }}\xrightarrow{{}}$ Whole number

NCERT Solutions for Class 7 Maths Exercise 2.4

Question 3.Find:

(i) $\frac{7}{3} \div 2$

(ii) $\frac{4}{9} \div 5$

(iii) $\frac{6}{{13}} \div 7$

(iv) $4\frac{1}{3} \div 3$

(v) $3\frac{1}{2} \div 4$

(vi) $4\frac{3}{7} \div 7$

Answer:

(i) $\frac{7}{3} \div 2 = \frac{7}{3} \times \frac{1}{2} = \frac{{7 \times 1}}{{3 \times 2}} = \frac{7}{6} = 1\frac{1}{6}$

(ii) $\frac{4}{9} \div 5 = \frac{4}{9} \times \frac{1}{5} = \frac{{4 \times 1}}{{9 \times 5}} = \frac{4}{{45}}$

(iii) $\frac{6}{{13}} \div 7 = \frac{6}{{13}} \times \frac{1}{7} = \frac{{6 \times 1}}{{13 \times 7}} = \frac{6}{{91}}$

(iv) $4\frac{1}{3} \div 3 = \frac{{13}}{3} \div 3 = \frac{{13}}{3} \times \frac{1}{3} = \frac{{13}}{9} = 1\frac{4}{9}$

(v) $3\frac{1}{2} \div 4 = \frac{7}{2} \div 4 = \frac{7}{2} \times \frac{1}{4} = \frac{7}{8}$

(vi) $4\frac{3}{7} \div 7 = \frac{{31}}{7} \div 7 = \frac{{31}}{7} \times \frac{1}{7} = \frac{{31}}{{49}}$

NCERT Solutions for Class 7 Maths Exercise 2.4

Question 4.Find:

(i) $\frac{2}{5} \div \frac{1}{2}$

(ii) $\frac{4}{9} \div \frac{2}{3}$

(iii) $\frac{3}{7} \div \frac{8}{7}$

(iv) $2\frac{1}{3} \div \frac{3}{5}$

(v) $3\frac{1}{2} \div \frac{8}{3}$

(vi) $\frac{2}{5} \div 1\frac{1}{2}$

(vii) $3\frac{1}{5} \div 1\frac{2}{3}$

(viii) $2\frac{1}{5} \div 1\frac{1}{5}$

Answer:

(i) $\frac{2}{5} \div \frac{1}{2} = \frac{2}{5} \times \frac{2}{1} = \frac{{2 \times 2}}{{5 \times 1}} = \frac{4}{5}$

(ii) $\frac{4}{9} \div \frac{2}{3} = \frac{4}{9} \times \frac{3}{2} = \frac{2}{3}$

(iii) $\frac{3}{7} \div \frac{8}{7} = \frac{3}{7} \times \frac{7}{8} = \frac{3}{8}$

(iv) $2\frac{1}{3} \div \frac{3}{5} = \frac{7}{3} \div \frac{3}{5} = \frac{7}{3} \times \frac{5}{3} = \frac{{35}}{9} = 3\frac{8}{9}$

(v) $3\frac{1}{2} \div \frac{8}{3} = \frac{7}{2} \div \frac{8}{3} = \frac{7}{2} \times \frac{3}{8} = \frac{{7 \times 3}}{{2 \times 8}} = \frac{{21}}{{16}} = 1\frac{5}{{16}}$

(vi) $\frac{2}{5} \div 1\frac{1}{2} = \frac{2}{5} \div \frac{3}{2} = \frac{2}{5} \times \frac{2}{3} = \frac{{2 \times 2}}{{5 \times 3}} = \frac{4}{{15}}$

(vii) $3\frac{1}{5} \div 1\frac{2}{3} = \frac{{16}}{5} \div \frac{5}{3} = \frac{{16}}{5} \times \frac{3}{5} = \frac{{16 \times 3}}{{5 \times 5}} = \frac{{48}}{{25}} = 1\frac{{23}}{{25}}$

(viii) $2\frac{1}{5} \div 1\frac{1}{5} = \frac{{11}}{5} \div \frac{6}{5} = \frac{{11}}{5} \times \frac{5}{6} = \frac{{11}}{6} = 1\frac{5}{6}$