Integers Ex-6.3

NCERT solutions for Maths Integers 

NCERT Solutions for Class 6 Maths Integers

Class –VI Mathematics

(Ex. 6.3)

Question 1.ubtract:

(a) 35 – (20)

(b) 72 – (90)

(c) (–15) – (–18)

(d) (–20) – (13)

(e) 23 – (–12)

(f) (–32) – (–40)

Answer:

(a) 35 – 20 = 15

(b) 72 – 90 = –18

(c) (–15) – (–18) = –15 + 18 = 3

(d) –20 – (13) = –20 – 13 = –33

(e) 23 – (–12) = 23 + 12 = 35

(f) (–32) – (–40) = –32 + 40 = 8

NCERT Solutions for Class 6 Maths Exercise 6.3

Question 2.Fill in the blanks with >, < or = sign:

(a)(–3) + (–6) _______________ (–3) – (–6)

(b)(–21) – (–10) _______________ (–31) + (–11)

(c)45 – (–11) _______________ 57 + (–4)

(d)(–25) – (–42) _______________ (–42) – (–25)

Answer:

(a) (–3) + (–6) $\boxed <$ (–3) – (–6)

(b) (–21) – (–10) $\boxed >$ (–31) + (–11)

(c) 45 – (–11) $\boxed >$ 57 + (–4)

(d) (–25) – (–42) $\boxed >$ (–42) – (–25)

Question 3.Fill in the blanks:

(a)(–8) + __________ = 0

(b)13 + __________ = 0

(c)12 + (–12) = __________

(d)(–4) + __________ = –12

(e)__________ – 15 = –10

Answer:

(a) (–8) + 8 = 0

(b) 13 + (–13) = 0

(c) 12 + (–12) = 0

(d) (–4) + (–8) = –12

(e) 5 – 15 = –10

NCERT Solutions for Class 6 Maths Exercise 6.3

Question 4.Find:

(a)(–7) – 8 – (–25)

(b)(–13) + 32 – 8 – 1

(c)(–7) + (–8) + (–90)

(d)50 – (–40) – (–2)

Answer:

(a) (–7) – 8 – (–25)

= –7 – 8 + 25

= –15 + 25

= 10

(b) (–13) + 32 – 8 – 1

= –13 + 32 – 8 – 1

= 32 – 22

= 10

(c) (–7) + (–8) + (–90)

= –7 – 8 – 90

= –105

(d) 50 – (–40) – (–2)

= 50 + 40 + 2

= 92