Fractions Ex-7.2

NCERT solutions for Maths Fractions 

NCERT Solutions for Class 6 Maths Fractions

Class –VI Mathematics

(Ex. 7.2)

Question 1.Draw number lines and locate the points on them:

(a)$\frac{1}{2},\frac{1}{4},\frac{3}{4},\frac{4}{4}$

(b)$\frac{1}{8},\frac{2}{8},\frac{3}{8},\frac{7}{8}$

(c)$\frac{2}{5},\frac{3}{5},\frac{8}{5},\frac{4}{5}$

Answer:

NCERT Solutions for Class 6 Maths Exercise 7.2

Question 2.Express the following fractions as mixed fractions:

(a)$\frac{{20}}{3}$

(b)$\frac{{11}}{5}$

(c)$\frac{{17}}{7}$

(d)$\frac{{28}}{5}$

(e)$\frac{{19}}{6}$

(f)$\frac{{35}}{9}$

Answer:

(a)

3\mathop{\left){\vphantom{1\begin{gathered}</p><p>{\text{ }}20 \\\\\\</p><p>\underline { – 18} \\\\\\</p><p>\underline {{\text{ 2}}} \\\\\\</p><p>\end{gathered} }}\right.</p><p>\!\!\!\!\overline{\,\,\,\vphantom 1{\begin{gathered}</p><p>{\text{ }}20 \\\\\\</p><p>\underline { – 18} \\\\\\</p><p>\underline {{\text{ 2}}} \\\\\\</p><p>\end{gathered} }}}</p><p>\limits^{\displaystyle\,\,\, 6}

(b)

5\mathop{\left){\vphantom{1\begin{gathered}</p><p>{\text{ 11}} \\\\\\</p><p>\underline { – 10} \\\\\\</p><p>\underline {{\text{ 1}}} \\\\\\</p><p>\end{gathered} }}\right.</p><p>\!\!\!\!\overline{\,\,\,\vphantom 1{\begin{gathered}</p><p>{\text{ 11}} \\\\\\</p><p>\underline { – 10} \\\\\\</p><p>\underline {{\text{ 1}}} \\\\\\</p><p>\end{gathered} }}}</p><p>\limits^{\displaystyle\,\,\, 2}

$\therefore$$\frac{{20}}{3} = 6\frac{2}{3}$

$\therefore$$\frac{{11}}{5} = 2\frac{1}{5}$

(c)

7\mathop{\left){\vphantom{1\begin{gathered}</p><p>{\text{ 17}} \\\\\\</p><p>\underline { – 14} \\\\\\</p><p>\underline {{\text{ 3}}} \\\\\\</p><p>\end{gathered} }}\right.</p><p>\!\!\!\!\overline{\,\,\,\vphantom 1{\begin{gathered}</p><p>{\text{ 17}} \\\\\\</p><p>\underline { – 14} \\\\\\</p><p>\underline {{\text{ 3}}} \\\\\\</p><p>\end{gathered} }}}</p><p>\limits^{\displaystyle\,\,\, 2}

(d)

5\mathop{\left){\vphantom{1\begin{gathered}</p><p>{\text{ 28}} \\\\\\</p><p>\underline { – 25} \\\\\\</p><p>\underline {{\text{ 3}}} \\\\\\</p><p>\end{gathered} }}\right.</p><p>\!\!\!\!\overline{\,\,\,\vphantom 1{\begin{gathered}</p><p>{\text{ 28}} \\\\\\</p><p>\underline { – 25} \\\\\\</p><p>\underline {{\text{ 3}}} \\\\\\</p><p>\end{gathered} }}}</p><p>\limits^{\displaystyle\,\,\, 5}

$\therefore$$\frac{{17}}{7} = 2\frac{3}{7}$

$\therefore$$\frac{{28}}{5} = 5\frac{3}{5}$

(e)

6\mathop{\left){\vphantom{1\begin{gathered}</p><p>{\text{ 19}} \\\\\\</p><p>\underline { – 18} \\\\\\</p><p>\underline {{\text{ 1}}} \\\\\\</p><p>\end{gathered} }}\right.</p><p>\!\!\!\!\overline{\,\,\,\vphantom 1{\begin{gathered}</p><p>{\text{ 19}} \\\\\\</p><p>\underline { – 18} \\\\\\</p><p>\underline {{\text{ 1}}} \\\\\\</p><p>\end{gathered} }}}</p><p>\limits^{\displaystyle\,\,\, 3}

(f)

9\mathop{\left){\vphantom{1\begin{gathered}</p><p>{\text{ 35}} \\\\\\</p><p>\underline { – 27} \\\\\\</p><p>\underline {{\text{ 8}}} \\\\\\</p><p>\end{gathered} }}\right.</p><p>\!\!\!\!\overline{\,\,\,\vphantom 1{\begin{gathered}</p><p>{\text{ 35}} \\\\\\</p><p>\underline { – 27} \\\\\\</p><p>\underline {{\text{ 8}}} \\\\\\</p><p>\end{gathered} }}}</p><p>\limits^{\displaystyle\,\,\, 3}

$\therefore$$\frac{{19}}{6} = 3\frac{1}{6}$

$\therefore$$\frac{{35}}{9} = 3\frac{8}{9}$

NCERT Solutions for Class 6 Maths Exercise 7.2

Question 3.Express the following as improper fractions:

(a)$7\frac{3}{4}$

(b)$5\frac{6}{7}$

(c)$2\frac{5}{6}$

(d)$10\frac{3}{5}$

(e)$9\frac{3}{7}$

(f)$8\frac{4}{9}$

Answer:

(a)$7\frac{3}{4} = \frac{{\left( {7 \times 4} \right) + 3}}{4} = \frac{{28 + 3}}{4} = \frac{{31}}{4}$

(b)$5\frac{6}{7} = \frac{{\left( {5 \times 7} \right) + 6}}{7} = \frac{{35 + 6}}{7} = \frac{{41}}{7}$

(c)$2\frac{5}{6} = \frac{{\left( {2 \times 6} \right) + 5}}{6} = \frac{{12 + 5}}{6} = \frac{{17}}{6}$

(d)$10\frac{3}{5} = \frac{{\left( {10 \times 5} \right) + 3}}{5} = \frac{{50 + 3}}{5} = \frac{{53}}{5}$

(e)$9\frac{3}{7} = \frac{{\left( {9 \times 7} \right) + 3}}{7} = \frac{{63 + 3}}{7} = \frac{{66}}{7}$

(f)$8\frac{4}{9} = \frac{{\left( {8 \times 9} \right) + 4}}{9} = \frac{{72 + 4}}{9} = \frac{{76}}{9}$